(4x^2-20x+9)/((2x-5)^2)

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Solution for (4x^2-20x+9)/((2x-5)^2) equation:


D( x )

(2*x-5)^2 = 0

(2*x-5)^2 = 0

(2*x-5)^2 = 0

2*x-5 = 0 // + 5

2*x = 5 // : 2

x = 5/2

x in (-oo:5/2) U (5/2:+oo)

(4*x^2-(20*x)+9)/((2*x-5)^2) = 0

(4*x^2-20*x+9)/((2*x-5)^2) = 0

4*x^2-20*x+9 = 0

4*x^2-20*x+9 = 0

DELTA = (-20)^2-(4*4*9)

DELTA = 256

DELTA > 0

x = (256^(1/2)+20)/(2*4) or x = (20-256^(1/2))/(2*4)

x = 9/2 or x = 1/2

(x-1/2)*(x-9/2) = 0

((x-1/2)*(x-9/2))/((2*x-5)^2) = 0

( x-1/2 )

x-1/2 = 0 // + 1/2

x = 1/2

( x-9/2 )

x-9/2 = 0 // + 9/2

x = 9/2

x in { 1/2, 9/2 }

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